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in Real Numbers by (48.8k points)
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Show that 5 + √7 is an irrational number.

1 Answer

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Let us assume that 5 + √7 is a rational number. So, we can find co-prime integers ‘a’ and ‘b’ (b ≠ 0) such that

Since, ‘a’ and ‘b’ are integers, \(\sqrt[a]{b}\) – 5 is a rational number and so √7 is a rational number. 

∴ But this contradicts the fact that √7 is an irrational number. 

Our assumption that 5 + √7 is a rational number is wrong. 

∴ 5 + √7 is an irrational number.

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