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in Linear Equations in Two Variables by (48.8k points)
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The ratio of incomes of two persons is 9 : 7. The ratio of their expenses is 4 : 3. Every person saves Rs 200, find the income of each.

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Let the income of first person be Rs x and that of second person be Rs y. 

According to the first condition, the ratio of their incomes is 9 : 7. 

∴ x/y = 9/7

∴ 7x = 9y 

∴ 7x – 9y = 0 …….(i) 

Each person saves Rs 200. 

Expenses of first person = Income – Saving 

= x – 200

Expenses of second person = y – 200 

According to the second condition, the ratio of their expenses is 4 : 3 

∴ (x - 200)/(y - 200) = 4/3

∴ 3(x – 200) = 4(y – 200) 

∴ 3x – 600 = 4y – 800 

∴ 3x – 4y = – 800 + 600 

∴ 3x – 4y = -200 …(ii) 

Multiplying equation (i) by 4, 

28x - 36y = 0 …(iii) 

Multiplying equation (ii) by 9, 

27x - 36y = -1800 …(iv) 

Subtracting equation (iv) from (iii),

Substituting x = 1800 in equation (i), 

7x – 9y = 0 

∴ 7(1800) – 9y = 0 

∴ 9y = 7 x 1800

∴ y = (7 x 1800)/9

y = 7 x 200 

∴ y = 1400 

∴ The income of first person is Rs 1800 and that of second person is Rs 1400.

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