Factorisation of -3a^2 + 3ab + 3ac is 3a(-a–b –c).

Question

State whether the statements are true (T) or false (F)

Factorisation of -3a² + 3ab + 3ac is 3a(-a–b –c).

Answer 1

False

Let us factorize -3a² + 3ab + 3ac.

-3a² + 3ab + 3ac = 3(-a×a + a×b + a×c)

⇒ -3a² + 3ab + 3ac = 3a (-a + b + c)

But, 3a (-a + b + c) ≠ 3a (-a – b – c)