(B) 2m – l
Explanation:
Let x be the lower class limit of a continuous frequency distribution
Let y be the upper class limit of a continuous frequency distribution
Now, according to the question,
Mid-point of a class = (x+y) /2
=m
x+y = 2m or, x+l=2m
It is given that, y = l = upper class limit
x=2m-l
Hence, the lower class limit of the class = 2m-l
Hence, option (B) is the correct answer.