Here,
a1 = 0
a2 = ¼
a3 = ½
a4 = ¾
a2 – a1 = ¼ – 0 = ¼
a3 – a2 = ½ – ¼ = ¼
a4 – a3 = ¾ – ½ = ¼
Since, difference of successive terms are equal,
Hence, 0, 1/4, 1/2, 3/4… is an AP with common difference ¼.
Therefore, the next three term will be,
¾ + ¼ , ¾ + 2(¼), ¾ + 3(¼)
1, 5/4 , 3/2