Question

During the decomposition of H₂O₂ to give dioxygen, 48g O₂ is formed per minute at certain point of time. The rate of formation of water at this point is ……………

(a) 0.75 mol min^-1

(b) 1.5 mol min^-1

(c) 2.25 mol min^-1

(d) 3.0 mol min^-1

Answer 1

(d) 3.0 mol min^-1

H₂O₂ → H₂O + \(\frac{1}{2}\)O₂

No. of moles of oxygen = \(\Big(\frac{48}{32}\Big)\) _{= 1.5 mol}

Rate of formation of oxygen = 2 x 1.5

= 3 mol min^-1