Given: a spherical ball salt, it is dissolving such that the rate of decrease of the volume at any instant is proportional to the surface
To prove: the radius is decreasing at a constant rate
Explanation: Let the radius of the spherical ball of the salt a t any time t be ‘r’.
Let the surface area of the spherical ball be S
Then, S = 4πr2……….(i)
Let V be the volume of the spherical ball,
Where k is the proportional constant
Substituting the values from equation (i) and (ii), we get
Hence the radius of the spherical ball is decreasing at a constant rate.
Hence Proved