Question

Find an angle θ, 0 < θ < π/2, which increases twice as fast as its sine.

Answer 1

Given: a condition 0 < θ < π/2.

To find the angle θ such that it increases twice as fast as its sine.

Explanation: Let x = sin θ

On differentiating with respect to t, we get

Now cancelling the like terms, we get

1 = 2cos θ