If [(2a,x1,y1),(2b,x2,y2),(2c,x3,y3)] = abc/2 ≠ 0, then the area of the triangle whose vertices are ((x1/a,y1/a)), ((x2/b,y2/b)), ((x3/c,y3/c)) is ...

Question

If \(\begin{bmatrix} 2a &x_1&y_1 \\[0.3em]2b&x_2&y_2\\2c&x_3&y_3\end{bmatrix}\) = abc/2 ≠ 0, then the area of the triangle whose vertices are (x₁/a,y₁/a), (x₂/b,y₂/b), (x₃/c,y₃/c) is ...

(a) 1/4

(b) (1/4) abc

(c) 1/8

(d) (1/8) abc

Answer 1

(c) 1/8

Given \(\begin{bmatrix} 2a &x_1&y_1 \\[0.3em]2b&x_2&y_2\\2c&x_3&y_3\end{bmatrix}\)= abc/2