Given numbers are 1095 and 1168.
The prime factorization of 1095 and 1168 gives:
Here, 731 is the smallest power of the common factor 73.
Therefore, the H.C.F of these two integers = 73
24 × 31× 51 × 731 are the greatest powers of the prime factors 2, 3, 5 and 73 respectively involved in the given numbers.
Now, L.C.M of 1485 and 4356 = 2 × 2 × 2 × 2 × 3 × 5 × 73= 17520