Question

ΔABC is right angled at A and AD ⊥ BC. If BC = 13 cm and AC = 5 cm, find the ratio of the areas of ΔABC and ΔADC.

Answer 1

Given: AD ⊥ BC

and BC = 13 cm and AC = 5 cm

Let △ABC and △ADC

∠A = ∠D [each 90°]

∠C = ∠C [common angle]

∴ △ABC ~ △ADC [by AA similarity]

We know that, the ratio of two similar triangles is equal to the square of the ratio of their corresponding sides.