Question

Two resistors of 5 Ω and 10 Ω are connected in parallel. Eight such sets are connected in series.

Find the equivalent resistance of this combination.

Answer 1

Equivalent resistance of the parallel combination is

R_p = \(\frac{r_1\,\times\,r_2}{r_1\,+\,r_2}\)

= \(\frac{5\,\times\,10}{5\,+\,10}\)

= \(\frac{50}{15}\)

= \(\frac{10}{3}\,\Omega\)

These eight resistances are connected in series, so

So, the equivalent resistance of the combination is \(\frac{80}{3}\,\Omega\)