Balanced equation: S + 6HNO3→ H2SO4 + 6NO2 + 2H2O
Step 1: Write the unbalanced equation
S + HNO3→ H2SO4 + NO2 + H2O
Step 2: Compare the number of atoms of reactants with the number of atoms of products.
|
Reactants (left side) |
Products (right side) |
Element |
Number of atoms |
Number of atoms |
S |
1 |
1 |
H |
1 |
4 |
O |
3 |
7 |
N |
1 |
1 |
Step 3: Now, first let us consider nitrogen atom. If we multiply 6 in the reactant (HNO3) and product (in NO2), we will get the equal number of atoms.
No. of atoms of nitrogen |
Reactant (in HNO3) |
Product (in NO2) |
Initially |
1 |
1 |
To balance |
1 x 6 = 6 |
1 x 6 = 6 |
Step 4: Write the resulting equation:
S + 6HNO3→ H2SO4 + 6NO2 + H2O
Step 5: Now check whether the equation is balanced or not by comparing the atoms
|
Reactants (left side) |
Products (right side) |
Element |
Number of atoms |
Number of atoms |
S |
1 |
1 |
H |
6 |
4 |
O |
18 |
17 |
N |
6 |
6 |
We find that the equation is not balanced yet. As the number of hydrogen and oxygen atoms are unequal on the two sides.
First balance the oxygen atom.
Step 6: If we multiply 2 in the product (in H2O) and 6, we will get the equal number of oxygen atoms on both sides.
No. of atoms of nitrogen |
Reactant (in HNO3) |
Product (in H2SO4 + + 6NO2 + H2O) |
Initially |
18 |
17 |
To balance |
18 |
4 + 12 + 2 x 1 = 18 |
Step 7: Write the resulting equation:
S + 6HNO3→ H2SO4 + 6NO2 + 2H2O
Step 8: Now check whether the equation is balanced or not by comparing the atoms.
|
Reactants (left side) |
Products (right side) |
Element |
Number of atoms |
Number of atoms |
S |
1 |
1 |
H |
6 |
6 |
O |
18 |
18 |
N |
6 |
6 |
Step 9: Write the resulting equation:
S + 6HNO3→ H2SO4 + 6NO2 + 2H2O
We find that the equation is balanced now.
Step 10: Write down the final balanced equation:
S + 6HNO3→ H2SO4 + 6NO2 + 2H2O