2x4 + 13x3 + 27x2 + 23x + 7,
x3 + 3x2 + 3x + 1, x2 + 2x + 1.
By division algorithm, first divide
∴ (x + 1)2 is G.C.D of x3 + 3x2 + 3x + 1 and x2 + 2x + 1.
Next let us divide
2x4 + 13x3 + 27x2 + 23x + 7 by x2 + 2x + 1
∴ G.C.D of 2x4 + 13x3 + 21x2 + 23x + 7, x3 + 3x2 + 3x + 1, x2 + 2x + 1 is (x + 1)2.