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Solve √(y + 1) + √(2y - 5) = 3.

1 Answer

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Best answer

Squaring both sides 

9y2 – 78y + 169 = 4 (y + 1)(2y – 5)

9y2 – 78y + 169 = 4 (2y2 + 2y – 5y – 5)

9y2 – 78y + 169 = 8y2 + 8y – 20y – 20

9y2 – 78y + 169 – 8y2 + 12y + 20 = 0

y2 – 66y + 189 = 0

y2 – 63y – 3y + 189 = 0

y(y – 63) – 3(y – 63) = 0

(y – 63)(y – 3) = 0

y = 63, 3

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