Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.7k views
in Physics by (51.5k points)
closed by

The power of a lens is + 1.5 D. Name the type of defects vision that can be corrected by using this lens. Find the focal length of the lens.

1 Answer

+1 vote
by (56.3k points)
selected by
 
Best answer

Power of a lens is = P = + 1.5 D. 

Since power is positive hence the lens used is a convex lens. 

Types of defects vision that can be corrected by using this lens Hypermetropia and presbyopia. 

A person suffering from any of these defects is not able to see the nearby objects clearly. 

The purpose of the convex lens is to increase the converging power of the lens and help to form the image of nearby objects on the retina. 

Focal length = f 

f = 1/P (in meters) 

= 1/1.5 m 

= 0.667 m

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...