Question

Find the area of the quadrilateral whose vertices taken in order are (- 4, -2), (-3, -5), (3, -2) and (2, 3).

Answer 1

Given: The vertices of the quadrilateral be A(-4, -2), B(-3, -5), C(3, -2) and D(2, 3).

Let join AC to form two triangles,

Now, We know that

Area of quadrilateral ABCD = Area of triangle ABC+ Area of triangle ACD

Hence, Area of quadrilateral ABCD = 28 square Units