Answer : (c) 384 π cm2
Total area cleaned at each sweep of the blades
= 2 × Area of sector cleaned by the sweep of one blade
= 2 × \(\big[\) \(\frac{120}{360}\times \pi \times (24)^2 \big]\) \(\big[\because radius\,of\,sector\,=\,length\,of\,blade\big]\)
= 384 π cm2.