Question

A solid iron pole is having a cylindrical portion 110 cm high and of base diameter, 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that mass of 1 cm³ of iron is 8 g.

Answer 1

= 339.428 cm³

Radius of the cylinder, R = Radius of cone = 6cm

Height of the cylinder, H = 110cm

Volume of cylinder = πR²H

= 22/7 x 6 x 6 x 110

= 12445.714cm³

Hence, the volume of the pole

= Volume of conical part + Volume of the cylindrical part

= 339.43 + 12445.714

= 12785.142 cm³

Required mass of pole = 8 × 12785.142

= 102281.13 gm

= 102.281kg