(c) \(\frac{47}{24}\)
Given exp.
= \(\bigg(\frac12\bigg)^2\times\bigg(\frac1{\sqrt2}\bigg)^2+4\times\bigg(\frac1{\sqrt3}\bigg)^2+\frac12\times(1)^2-2\times0\)
= \(\frac14\times\frac12+4\times\frac13+\frac12=\frac18+\frac43+\frac12=\frac{3+32+12}{24}=\frac{47}{24}\)