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+1 vote
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in Trigonometry by (46.3k points)
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The value of \(\frac12\) sin2 90° sin2 30° cos2 45° + 4 tan2 30° + \(\frac12\) sin2 90° – 2 cos2 90° is:

(a) \(\frac{45}{24}\)

(b) \(\frac{46}{24}\)

(c) \(\frac{47}{24}\)

(d) \(\frac{49}{24}\)

1 Answer

+1 vote
by (49.3k points)
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Best answer

(c) \(\frac{47}{24}\)

Given exp.

\(\bigg(\frac12\bigg)^2\times\bigg(\frac1{\sqrt2}\bigg)^2+4\times\bigg(\frac1{\sqrt3}\bigg)^2+\frac12\times(1)^2-2\times0\)

\(\frac14\times\frac12+4\times\frac13+\frac12=\frac18+\frac43+\frac12=\frac{3+32+12}{24}=\frac{47}{24}\)

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