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The minimum value of the expression ((3b+4c)/a)+((4c+a)/3b)+((a+3b)/4c)

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The minimum value of the expression \(\bigg(\frac{3b+4c}{a}\bigg)+\bigg(\frac{4c+a}{3b}\bigg)+\bigg(\frac{a+3b}{4c}\bigg) \) (a, b, c are +ve) is

(a) 1 

(b) 4 

(c) 6 

(d) 8

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(c) 6

∴ Minimum value of the expression is 6.

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