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+1 vote
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in Matrices by (27.4k points)
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If A = \(\begin{bmatrix} n &0 & 0 \\[0.3em] 0 &n & 0 \\[0.3em] 0 & 0 & n \end{bmatrix}\) and B = \(\begin{bmatrix} a_1 &a_2 & a_3 \\[0.3em] b_1 &b_2 & c_3 \\[0.3em] c_1 & c_2 & c_3 \end{bmatrix}\), then AB is equal to :

A. B 

B. nB 

C. Bn 

D. A + B

1 Answer

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by (27.0k points)
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Best answer

 (B). nB

AB = \(\begin{bmatrix} n &0 & 0 \\[0.3em] 0 &n & 0 \\[0.3em] 0 & 0 & n \end{bmatrix}\)x \(\begin{bmatrix} a_1 &a_2 & a_3 \\[0.3em] b_1 &b_2 & c_3 \\[0.3em] c_1 & c_2 & c_3 \end{bmatrix}\) 

Option (B) is the answer.

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