Question

What length of tarpaulin 3m wide will be required to make a conical tent of height 8m and base radius 6m ? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20cm. (Use π = 3.14).

Answer 1

We have, 

Height of tent = 8m 

Base radius = 6m 

Slant height (l) = \(\sqrt{r^2+h^2}\) 

=\(\sqrt{36+64}\) 

= 10 m

Curved surface area of the cone = πrl 

= 3.14 × 6 × 10m² 

∴Length of 3 m wide tarpaulin required

= \(\frac{3.14\times 6 \times 10}{3}\) 

= 62.8 m

Extra length required for stitching and cutting wastage = 0.2 m 

Total length required = 62.8 + 0.2 = 63m