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in Surface Areas And Volumes by (42.6k points)
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What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6m? Assume that extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use π = 3.14) 

[Note : Take 20 cm as 0.6m2 ]

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Radius of the cone, r = 6 m 

Height of the cone, h = 8 m

∴ C.S.A. = πrl = 3.14 x 6 x 10 = 188.4 m2 

Let the length of the tarpaulin = l 

∴ Area of the tarpaulin, lb = 188.4 + 0.6 

= 189 m2 

⇒ 3l = 189 

⇒ l = 189/3 = 63m

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