Question

In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.

Answer 1

Here, Initial count of bacteria, `P = 506000`
The rate at which count is increasing, `r = 2.5 %` per hour
Time, `t = 2` hours
So, bacteria after two hours ` = P(1+r/100)^t`
`=506000**(102.5/100)**(102.5/100)`
`= 506000**(41/40)**(41/40) = 531616`