Given :
PQ = 5 cm , QR = 6.5 cm , \(\angle P=100^\circ,\angle R=100^\circ,\angle S=75^\circ\)
Answer :
Sum of all angles of a quadrilateral is 360
Construction :
Step 1 : Draw segment PQ of length 5 cm.
Step 2 : Draw angle PQC of 85 degrees.
Step 3 : Taking Q as centre draw arc of radius 6.5 cm which cuts the segment QC. Point of intersection is R
Step 4 : Draw angle QRF of 100 degrees.
Step 5 : Draw angle QPG of 100 degrees.
Step 6 : Point of intersection of segments PG and RF is S
PQRS is the required quadrilateral.
