Given :
AB = 4 cm , AC = 5 cm , AC = 5.5 cm \(\angle ABC\) = \(\angle ACD=90^\circ\)
Construction :
Step 1 : Draw segment AB of length 4 cm.
Step 2 : Draw angle ABP of 90 degrees.
Step 3 : Taking A as centre draw arc of radius 5 cm which cuts the segment BP. Point of intersection is C.
Step 4 : Join AC.
Step 5 : Draw angle ACD of 90 degrees.
Step 6 : Taking A as centre draw arc of radius 5.5 cm which cuts the segment CF. Point of intersection is D.
Step 4 : Join AD.
ABCD is the required quadrilateral.
