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If the lines p1x + q1y = 1, p2x + q2y = 1 and p3x + q3y = 1 be concurrent, show that the points (p1, q1), (p2, q2) and (p3, q3) are collinear.

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Given: 

p1x + q1y = 1 

p2x + q2y = 1 

p3x + q3y = 1 

To prove: 

The points (p1, q1), (p2, q2) and (p3, q3) are collinear.

Concept Used: 

If three lines are concurrent then determinant of equation is zero. 

Explanation: 

The given lines can be written as follows: 

p1 x + q1 y – 1 = 0 … (1) 

p2 x + q2 y – 1 = 0 … (2) 

p3 x + q3 y – 1 = 0 … (3) 

It is given that the three lines are concurrent.

Hence proved, This is the condition for the collinearity of the three points, (p1, q1), (p2, q2) and (p3, q3).

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