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If D is a point on the side AB of `Delta ABC` such that `AD:BD=3:2 and E` is a point on BC such that `DE||AC`, find the ratio of the areas of `Delta ABC and Delta DBE`
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Let `AD = 3x cm and DB=2x cm`. Then,
`AB= (AD+DB)=(3x+2x) cm =5cm`.
In `Delta ABC and Delta DBE` we have
`angle CAB= angle EDB` [ corresponding `angle`]
and ` angle AC~ angle DEB` [ corresponding `angle`]
` :. Delta ABC~ Delta DBE`[ by AA- similarity]
`rArr (ar (Delta ABC))/(ar (Delta DBE))=((AB)^(2))/((DB)^(2))=((5x))/((2x)^(2))=(25x^(2))/(4x^(2)) =(25)/(4)`
`rArr ar (Delta ABC) : ar (Delta DBE)= 25.4`

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