Question

The pressure of 20L of a gas kept at 300 K is found to be 2 atoms. If the pressure is increased to 3 atom at the same temperature, what will be the new volume?

Answer 1

According to Boyles law, Pv = a constant 

Therefore, P₁V₁ = P₂V₂ 

Here, P₁ = 2atm V₁ = 20L P₂ = 3atm V₂ =? 

∴ 2 × 20 = 3 × V₂

Thus, v₂ = \(\frac{2\times20}{3}\) = 13.3L