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Find the two natural numbers which differ by 5 and the sum of whose squares is 97.

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Let the two numbers be x and x + 5.

From the given information,

x2 + (x + 5)2 = 97

2x2 + 10x + 25 − 97 = 0

2x2 + 10x − 72 = 0

x2 + 5x − 36 = 0

(x + 9) (x − 4) = 0

x = − 9 or 4

Since, − 9 is not a natural number. So, x = 4.

Thus, the numbers are 4 and 9.

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