Question

A particle moves on circular path of radius 5 m with constant speed 5 m/s. Find the magnitude of its average acceleration when it completes half revolution.

Answer 1

`t = (piR)/(v) = (pi xx 5)/(5) = pi sec`
`Delta vecv = (-5 hati) - (5hati) = -10 hati`
`veca_("avg") = (Delta vecv)/(t) = (-10hati)/(pi) rArr |veca _("avg")| = (10)/(pi) m//s^(2)`