Pls ans it experts

Question

Answer 1

The straight line AB has x-intercept = 5 and y-intercept = 5.

Hence equation is

x/5+y/5=1

=> x+y=5

So the cordinates of the points on the side AB,having only integer values are

(0,5);(1,4);(2,3);(3,2);(4,1)and (5,0)

On OB these points are

(0,0);(0,1);(0,2);(0,3);(0,4);(0,5)

And on OA these points are

(1,0);(2,0);(3,0);(4,0);(5,0)

Hence the following points with integer value of coordinates are  lying strictly inside the triangle OAB

(1,1);(2,1);(3,1);(1,2);(2;2);(1,3)

So total 6 points