Question

A hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm. The volume of steel used is ....(Use π = 3.141)

(A) 42.15 cm³

(B) 41.52 cm³

(C) 41.25 cm³

(D) 40 cm³

Answer 1

The correct option is: (C) 41.25 cm³

Explanation:

Let r and R be inner and outer radius of bowl respectively,

Then, r = 5 cm, R = 5 + 0.25 = 5.25 cm.

Volume of steel used = Outer volume - Inner volume