Given: Sharmila’s yearly salary = Rs. 5,00,000.
Rate of annual increment = 10 %.
Here, a = a1 = 5,00,000
a2 = 5,00,000 × \(\frac{11}{10}\) = 5,50,000
a3 = 5,00,000 × \(\frac{11}{10}\) × \(\frac{11}{10}\) = 6,05,000
a4 = 5,00,000 × \(\frac{11}{10}\) × \(\frac{11}{10}\) × \(\frac{11}{10}\) = 6,65,000
Every term starting from the second can be obtained by multiplying its pre¬ceding term by a fixed number \(\frac{11}{10}\).
∴ r = common ratio = \(\frac{11}{10}\)
Hence the situation forms a G.P.