Angle subtended by the chord = 90°
Radius of the circle = 10 cm
Area of the minor segment = Area of the sector
POQ – Area of △POQ
Area of the sector = \(\frac{x}{360}\) × πr
\(\frac{90
}{360}\) × 3.14 × 10 × 10 = 78.5
Area of the triangle = \(\frac{1}{2}\) × base × height
= \(\frac{1}{2}\) × 10 × 10 = 50
∴ Area of the minor segment = 78.5 – 50 = 28.5 cm2
Area of the major segment = Area of the circle – Area of the minor segment
= 3.14 × 10 × 10 – 28.5
= 314 – 28.5 cm2
= 285.5 cm2
