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A chord of a circle of radius 10 cm. subtends a right angle at the centre. Find the area of the corresponding minor segment (use π = 3.14),

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Radius of circle (r) = 10 cm 

Sector angle (x) = 90° 

Radius of sector (r) = 10 cm.

Area of the Minor Segment = Area of sector OACB – Area of Δ OAB 

= 78.5 – 50.0 = 28.5 cm2

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