Question

In a triangle PQR with right angle at Q, the value of ∠P is x, PQ = 7 cm and QR = 24 cm, then find sin x and cos x.

Answer 1

Given right angled triangle is PQR with right angle at Q. The value of ∠P is x.

By Pythagoras theorem 

PR² = PQ² + QR² 

PR² = 7² + 24² 

PR² = 49 + 576 

PR² = 625 

PR² = √625 = 25 

sin x = \(\frac{QR}{PR}\) = \(\frac{24}{25 }\)

cos x = \(\frac{PQ}{PR}\) = \(\frac{7}{25 }\)

Answer 2

Step 1: Use pythagoras theorem. 

Step 2: Use sin formula.