Given a1 = 15 and a1 + a2 + a3 =102
a + a + d + a + 2d = 102
⇒ 3a + 3d = 102
⇒ 3 (a + d) = 102
∴ (a + d) = 102/3 = 34
⇒ d = 34 – a = 34 – 15 = 19
∴ a = 15, 0 = 19
then its 10th term = a10
= a + (10 – 1)d
= a + 9d = 15 + 9(19)
= 15 + 171 = 186
∴ 10th term of it = 186