Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Arithmetic Progression by (41.7k points)
closed by

nth term of an A.P. is an . If a1 + a2 + a3 = 102 and a1 = 15, then find a10 .

1 Answer

+1 vote
by (41.9k points)
selected by
 
Best answer

Given a1 = 15 and a1 + a2 + a3 =102 

a + a + d + a + 2d = 102

⇒ 3a + 3d = 102 

⇒ 3 (a + d) = 102 

∴ (a + d) = 102/3 = 34 

⇒ d = 34 – a = 34 – 15 = 19 

∴ a = 15, 0 = 19 

then its 10th term = a10 

= a + (10 – 1)d 

= a + 9d = 15 + 9(19) 

= 15 + 171 = 186 

∴ 10th term of it = 186

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...