length of a vertical pole and length of its shadow are in direct proportion.
⇒ \(\frac{x_1}{y_1}= \frac{x_2}{y_2}\)
i) x1 = 5.6
y1 = 3.2
x2 = 10.5
y2 = ?
⇒ y2 = \(\frac{x_2 \,\times\,y_1}{x_1}\) = \(\frac{10.5 \,\times\,3.2}{5.6}\) = 6 m
∴The length of the shadow = 6 cm
ii) x1 = 5.6
y1 = 3.2
x2 = ?
y2 = 5
⇒ \(\frac{x_1}{y_1}= \frac{x_2}{y_2}\)
x2 = \(\frac{x_1 \,\times\,y_2}{y_1}\) = \(\frac{5.6 \,\times\,5}{3.2}\) = \(\frac{35}4\) = 8.75 m .
∴ x2 = 8.75
