Correct option is c. x = 0
Let P(at2 , 2at) lies on the parabola
y2 = 4ax
Mid point of PS is Q.
h = \(\frac{at^2+a}{2},K=\frac{0+2at}2\)
\(\frac{2h-a}a=t^2,\frac{K}a=t\)
\(\frac{2h-a}a=\frac{K^2}a\)
a(2h – a) = k2
Locus of (h, k) is y2 =2a x - a/2
Equaiton of directrix is \(x-\frac{a}2=-\frac{a}2\)
x = 0