Correct option is c. π/3
Equation of tangent of the parabola y2 = 4x is
y = mx + 1/m
This equation passes through (1, 4) i.e.
4 = m +1/m
m2 – 4m+1 = 0
m1 .m2 = 1 and m1 + m2 = 4
Angle between the two tangents is tan θ = \(\begin{vmatrix}\frac{m_!-m_2}{1+m_1m_2}\end{vmatrix}\)
tanθ = \(\begin{vmatrix}\frac{\sqrt{(4)^2-4}}{1+1}\end{vmatrix}=\frac{\sqrt{12}}2=\sqrt{3}\)
∴θ = π/3