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+1 vote
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in Determinants by (51.1k points)
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If \(\begin{vmatrix} (a_1 - b_1)^2& (a_1 -b_2)^2&(a_1 - b_3)^2\\(a_2 - b_1)^2&(a_2 -b_2)^2&(a_2 - b_3)^2\\(a_3-b_1)^2&(a_3 - b_2)^2&(a_3 - b_3)^2\end{vmatrix}\) = k(a1 – a2)(a2 – a3)(a3 – a1)(b1 – b2)(b2 – b3)(b3 – b1), then k is equal to

(a) 1

(b) 2

(c) 4

(d) 8

1 Answer

+1 vote
by (51.4k points)
selected by
 
Best answer

Correct option is (b) 2

The given determinant can be written as

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