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The rate of particular reaction doubles when temperature changes from 27°C to 37°C. Calculate the energy of activation.

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The rate of particular reaction doubles when temperature changes from 27°C to 37°C. Calculate the energy of activation.

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Given that T1 = 27°C = 273 +21 = 300K

T2 = 37°C = 273 + 37 = 310K

k2 = 2k1

Substituting these values in the equation.

This as solving for Ea

Ea = 53598.6 J mol-1 or 53.6 kJ mol-1

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