Question

The activation energy of a reaction is 94.14 kJ mol^-1 and the value of the rate constant at 313K. is 1.8 x 10^-1 sec^-1. Calculate the frequency factor (A).

Answer 1

Given that, E_a = 94.14 kJ mol^-1 = 9414 J mol^-1

T = 313K,

k = 1.8 x 10^-1 sec^-1 Substituting these values in

= (log 1.8 – 5) + 15.7082

= (0.2553 – 5) + 15.708

= 10.963J

A = Anti log (10.963 J)

= 9.194 x 10^-10 sec