Question

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is 

(a) 1.520 

(b) 0.995 

(c) 19.00

(d) 9.00

Answer 1

Correct option is (d) 9.00

\(\frac{\text{Wt. of hydroxide}}{E_M + E_{OH^-}}= \frac {\text{Wt. of oxide}}{E_M+ E_O}\)

or, \(\frac{1.520}{E_M+17}= \frac{0.995}{E_M+8}\)

or, E_M = 9.00