The concerned chemical reaction is
\(\underset{\;\\1 \text{ mole}}{\underset{\;||\\CH_2}{CH_2}} + \underset{\;\\160 g}{Br_2} \longrightarrow \underset{|\\CH_2Br}{CH_2Br}\)
1 mole of ethylene absorbs 160 g of bromine 0.1 mole of ethylene will absorb 16 g of bromine.