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4.35 g of a sample of pyrolusite (MnO2) when heated with conc. HCI gave chlorine. The chlorine when passed through potassium iodide solution liberated 6.35 g of iodine. The percentage purity of the pyrolusite sample is

(a) 40

(b) 50

(c) 60

(d) 70

1 Answer

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Best answer

Correct option is (b) 50

MnO2 + 4HCI → 2MnCl2 + Cl2 + 2H2O; 

2KI + Cl→ 2KCl + I2

Moles of 12 liberated moles of Cl2 = moles of MnO2 = \(\frac{6.35}{254}\)

Weight of pure MnO2 \(\frac{6.35 \times 87}{254}\) = 2.175

% Purity of MnO2 = \(\frac{2.175 \times 100}{4.35} \) = 50

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