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in Determinants by (40.4k points)
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निम्न सारणिक को हल कीजिए  \(\begin{vmatrix}1&2&3\\ 4&x&6\\ 7&8&9\end{vmatrix}\) = 0.

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  \(\begin{vmatrix}1&2&3\\ 4&x&6\\ 7&8&9\end{vmatrix}\) = 0.

R1 के सापेक्ष प्रसार करने पर,

⇒ = 1(9x – 48) – 2(36 – 42) + 3(32 – 7x) = 0

⇒ 9x – 48 + 12 + 96 – 21x = 0

⇒ – 12x + 60 = 0

⇒ – 12x = – 60

x = 60/12=5

अतः x = 5.

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