Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
244 views
in Constructions by (15 points)
edited by

Construct a quadrilateral PQRS in which PQ = 5 cm, QR = 6.5 cm, ∠P = ∠R = 100° and ∠S = 75°.

Please log in or register to answer this question.

1 Answer

0 votes
by (47.8k points)

∵ ∠P + ∠Q + ∠R + ∠S = 360°

∴ 100° + ∠Q + 100° + 75° = 360°

⇒∠Q + 275° = 360°

⇒ ∠Q = 360° − 275°

∴ ∠Q = 85°

Steps of Construction :

Steps of Construction

(i) Draw a line segment PQ = 5 cm.

(ii) At Q, draw a ray QX making an angle of 85° and cut off QR = 6.5 cm.

(iii) At R, draw a ray making an angle of 100° and at, P, another ray making an angle of 100° which intersect each other at S.

then ∠S = 75°.

PQRS is the required quadrilateral.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...